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In isoscelent triangle with ACD or ABC,/AB/=/AC/=4, angle BAC=30 and /CN/ altitude.find /BN/ with diagram

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isosceles -- don't be insolent ...
Let AM be the altitude from A to BC
∆AMB ~ ∆CNB
so
BN/CN = BM/AM
BM = 4 sin15°
Now you can find BN

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