The hysteresis band for an inverting Schmitt trigger is given by the formula:
H = (R1 + R2) * (Vref / Vsat)
Where:
H = Hysteresis band
R1 = resistance connected between the inverting input and the output of the op-amp
R2 = feedback resistance connected between the non-inverting input and the output of the op-amp
Vref = reference voltage
Vsat = output saturation voltage of the op-amp
Plugging in the given values:
H = 3.0V
R2 = 10kΩ
Vref = 4.5V
Vsat = 9V
Rearranging the equation to solve for R1:
R1 = (H * Vsat) / (Vref) - R2
Substituting the values:
R1 = (3.0V * 9V) / (4.5V) - 10kΩ
R1 = (27V^2) / (4.5V) - 10kΩ
R1 = 6kΩ - 10kΩ
R1 = -4kΩ
Since the resistance value cannot be negative, it seems there might be an error in the given parameters or calculations. Please double-check the given values and ensure the calculations are correct.
in Inverting Schmitt Trigger, Given R2=10kΩ, Vref=4.5V and the output saturation voltage of the op-amp is 9V. Determine the value of R1 to achieve a hysteresis band of 3.0V. Express your answer in kohms
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