In humans, dimples are a dominant trait. Predict the percentage of children that will have dimples if one parent is heterozygous for dimples and the other parent does not have dimples.(1 point)

Responses

100 percent
100 percent

25 percent
25 percent

50 percent
50 percent

0 percent

1 answer

To predict the percentage of children that will have dimples, we can use a Punnett square.

Let's denote:

  • D = allele for dimples (dominant)
  • d = allele for no dimples (recessive)

If one parent is heterozygous for dimples, their genotype will be Dd, and the other parent, who does not have dimples, will have a genotype of dd.

The possible combinations from a Punnett square would be:

       D      d
     __________
d |    Dd    |  dd  |
     __________
d |    Dd    |  dd  |
     __________

From this, we can see the possible offspring genotypes are:

  • 50% Dd (have dimples)
  • 50% dd (do not have dimples)

Therefore, 50% of the children will have dimples.

So the correct response is:

50 percent