The man's genotype is Bb.
The punnett square for this marriage would look like this:
B b
-------------------
b | Bb bb
-------------------
b | Bb bb
Therefore, the genotypes of the children would be:
- 2 children would be bb (blue-eyed)
- 1 child would be Bb (brown-eyed)
In humans,brown eyes (B) are dominant over blue (b). A brown-eyed man marries a blue eyed woman and they have three children,two of whom is blue-eyed.Draw the punnett square that illustrates this marriage. What is the man’s genotype? What are genotypes of the children.
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