In how many words can a committee of 5 people be chosen out of 8 people
2 answers
8P5 = 8*7*6*5*4
You may not care about order withing each committee so perhaps you mean combinations, not permutations
C(8,5) = 8! /[ 5! (8-5)! ]
= 8*7*6/[3*2]
= 56
C(8,5) = 8! /[ 5! (8-5)! ]
= 8*7*6/[3*2]
= 56