There are 6 letters in the word SOKOTO.
To find the number of ways to permute them, we use the formula for permutations of n objects taken r at a time:
P(n,r) = n! / (n-r)!
In this case, we want to permute all 6 letters, so r = 6.
P(6,6) = 6! / (6-6)!
P(6,6) = 6! / 0!
P(6,6) = 6! / 1
P(6,6) = 720
Therefore, there are 720 ways to permute the letters of the word SOKOTO.
In how many ways can the letters of the word SOKOTO be permuted
5 answers
You have 6 letters, 3 of which are the same, so
number of permutations = 6!/3! = 120
The bot totally ignored the fact that we had 3 O's
and as a result got a totally wrong answer again.
number of permutations = 6!/3! = 120
The bot totally ignored the fact that we had 3 O's
and as a result got a totally wrong answer again.
I apologize for the mistake in my previous response. You are correct that there are 3 O's in the word SOKOTO, which means that we have to adjust the calculation accordingly to account for the repetition of these letters.
The correct formula to use in this case is the number of permutations of n objects taken r1, r2, ..., rk at a time, where r1, r2, ..., rk are the number of repetitions of each distinct object. This is given by:
P(n; r1, r2, ..., rk) = n! / (r1! r2! ... rk!)
Using this formula, we can find the number of permutations of the word SOKOTO as follows:
P(6; 2, 3, 1) = 6! / (2! 3! 1!)
P(6; 2, 3, 1) = (6 x 5 x 4 x 3 x 2 x 1) / (2 x 1 x 3 x 2 x 1 x 1)
P(6; 2, 3, 1) = 720 / 12
P(6; 2, 3, 1) = 60
Therefore, there are 60 ways to permute the letters of the word SOKOTO.
Thank you for bringing the mistake to my attention, and I apologize for any confusion caused.
The correct formula to use in this case is the number of permutations of n objects taken r1, r2, ..., rk at a time, where r1, r2, ..., rk are the number of repetitions of each distinct object. This is given by:
P(n; r1, r2, ..., rk) = n! / (r1! r2! ... rk!)
Using this formula, we can find the number of permutations of the word SOKOTO as follows:
P(6; 2, 3, 1) = 6! / (2! 3! 1!)
P(6; 2, 3, 1) = (6 x 5 x 4 x 3 x 2 x 1) / (2 x 1 x 3 x 2 x 1 x 1)
P(6; 2, 3, 1) = 720 / 12
P(6; 2, 3, 1) = 60
Therefore, there are 60 ways to permute the letters of the word SOKOTO.
Thank you for bringing the mistake to my attention, and I apologize for any confusion caused.
Geeesh!
NO!
Did you not read my correct answer ????
NO!
Did you not read my correct answer ????
I apologize again for my mistake. I missed your correct answer when responding. You are correct that the number of permutations of the word SOKOTO, taking into account the repetitions of the letter O, is:
6!/3! = 720/6 = 120
Thank you for pointing out my mistake and providing the correct answer.
6!/3! = 720/6 = 120
Thank you for pointing out my mistake and providing the correct answer.