10
There are 5 singers to choose from, and we need to select 3 of them. This can be calculated using the combination formula:
C(n, k) = n! / k!(n-k)!
So, C(5, 3) = 5! / 3!(5-3)! = 5! / 3!2! = 120 / 12 = 10
Therefore, there are 10 ways to select 3 singers from 5 who came to the audition.
In how many ways can 3 singers be selected from 5 who came to an audition?
(1 point)
Responses
1
1
10
10
5
5
60
1 answer