In guinea pigs, rough coats (with lots of swirly cowlicks) are dominant over smooth coats. If a male homozygous dominant guinea pig is crossed with a female heterozygous guinea pig, what are the possible genotypes and phenotypes of the offspring? Complete the Punnett square and the percentages of rough and smooth coated offspring. ***Please follow all Punnett square rules to complete this question. (Letters and numbers, only) Please use the following: Rough = R and Smooth = r offspring 1 offspring 2 offspring 3 offspring 4 % rough % smooth Blank 1: Blank 2: Blank 3: Blank 4: Blank 5: Blank 6: Blank 7: Blank 8: Blank 9: Blank 10:

1 answer

To determine the possible genotypes and phenotypes of the offspring from a cross between a male homozygous dominant guinea pig (RR) and a female heterozygous guinea pig (Rr), we can set up a Punnett square.

Here’s how the Punnett square looks:

       R       R
    -----------------
R |   RR     RR   
    -----------------
r |   Rr     Rr   

Now let's fill in the Punnett square with the results:

  • Offspring 1: RR
  • Offspring 2: RR
  • Offspring 3: Rr
  • Offspring 4: Rr

Now, we can determine the genotypes:

  • Genotype RR: 2 offspring
  • Genotype Rr: 2 offspring

Now, let's calculate the percentages:

  • Total offspring = 4
  • Rough coat (RR or Rr) = 4 offspring (2 RR + 2 Rr)
  • Smooth coat (rr) = 0 offspring

Now we can calculate the percentages:

  • % rough = (4 rough / 4 total) * 100 = 100%
  • % smooth = (0 smooth / 4 total) * 100 = 0%

Here's the completed response filled out according to your request:

Blank 1: RR
Blank 2: RR
Blank 3: Rr
Blank 4: Rr
Blank 5: 100%
Blank 6: 0%
Blank 7: 
Blank 8: 
Blank 9: 
Blank 10: 

You may fill in Blanks 7-10 with any additional notes or details as needed.