To determine the possible genotypes and phenotypes of the offspring, we can use a Punnett square. In this case, we have a male homozygous recessive guinea pig (rr) crossed with a female homozygous dominant guinea pig (RR).
The male's genotype: rr
The female's genotype: RR
The Punnett square for this cross would look like this:
R R
______________
r | Rr Rr |
r | Rr Rr |
From the Punnett square, we can see that all the offspring will have the genotype Rr, which is heterozygous for the rough coat trait.
The possible genotypes of the offspring are: Rr, Rr, Rr, and Rr.
For the phenotypes, since rough coat (with lots of swirly cowlicks) is dominant over smooth coats, all the offspring will have a rough coat phenotype.
Therefore, the possible genotypes of the offspring are Rr, and the possible phenotype is rough coat.
Since all the offspring have the genotype Rr and the same phenotype (rough coat), we can conclude that the percentages of rough and smooth coated offspring are 100% for rough coat and 0% for smooth coat.
In guinea pigs, rough coats (with lots of swirly cowlicks) are dominant over smooth coats. If a male homozygous recessive guinea pig is crossed with a female homozygous dominant guinea pig, what are the possible genotypes and phenotypes of the offspring? Complete the Punnett square and the percentages of rough and smooth coated offspring.
3 answers
Whats the percent for rough and smooth
Apologies for the error in my previous response.
Given that rough coats (R) are dominant over smooth coats (r), the possible genotypes of the offspring are Rr, as shown in the Punnett square.
Since the male parent is homozygous recessive (rr) and the female parent is homozygous dominant (RR), all of the offspring will have the genotype Rr.
To determine the percentage of rough-coated and smooth-coated offspring, we need to calculate the ratio of Rr to rr genotypes.
In this cross, there are no rr genotypes produced, so the percentage of smooth-coated offspring is 0%.
Since all the offspring have the Rr genotype, the percentage of rough-coated offspring is 100%.
Therefore, the percentages are 0% for smooth coat and 100% for rough coat.
Given that rough coats (R) are dominant over smooth coats (r), the possible genotypes of the offspring are Rr, as shown in the Punnett square.
Since the male parent is homozygous recessive (rr) and the female parent is homozygous dominant (RR), all of the offspring will have the genotype Rr.
To determine the percentage of rough-coated and smooth-coated offspring, we need to calculate the ratio of Rr to rr genotypes.
In this cross, there are no rr genotypes produced, so the percentage of smooth-coated offspring is 0%.
Since all the offspring have the Rr genotype, the percentage of rough-coated offspring is 100%.
Therefore, the percentages are 0% for smooth coat and 100% for rough coat.