I have no idea what the figure shows, my crystal ball is broken. On the line "figure contain", is that on the x axis, or y axis?
If it is on the x axis, notice that in between x=0 and x=1m, the two forces oppose, so in your calcualtions, watch sign. So the potentials due to those charges are opposite signs.
Elctric potential at x = kq(-2q/x^2 + 5q/(1-x)^2)
In (Figure 1), the charge q=1.28×10^−9 C.
figure contain ( -2q at 0 and +5q at 1m )
a) Find the electric potential at x=0.750 m.(include appropriate units)
b) Find the value of x between 0 and 1.00 m where the electric potential is zero. (include appropriate units)
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