In Fig. 4-11, a ball is launched with a velocity of 7.50 m/s, at an angle of 50° to the horizontal. The launch point is at the base of a ramp of horizontal length d1 = 4.00 m and height d2 = 3.60 m. A plateau is located at the top of the ramp.
What is the magnitude of its displacement from the launch point when it lands?
I just mainly want to make sure my math is right since this is my last try.
vy=7.5cos50
vy=5.745
dymax=vo^2/2g
dymax=(5.745)^2/19.6
dymax=1.684
My one question here is whether or not I assume this is where it hits the ramp, since there is no way to reach the plateau. If not, how would I find where it actually hits the ramp.
dymax=1/2gt^2
t=(2dymax/g)^1/2
t=.586
dx=vxt
dx=4.821 x .586
dx=2.825
I didn't use the time for it to go back down since the ball hits the ramp. Where am I going wrong?
1 answer