well, using the law of cosines,
f^2 = 6^2 + 11^2 - 2(6)(11) cos73°
f = 10.88
now, using the law of sines,
sinG/6 = sin73°/10.88
In ∆FGH, FH=6 ft, FG=11 ft, and m∠F=73°. Find m∠G to the nearest degree. *Hint: Law of Cosines
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