In eight days, a certain amount of Vanadium-48, V^48, decays to 1 over square root 2 of its original amount. What is the half life of Vanadium-48?

Answer 1

P*V = k
200*32 = V*40

Answer 2

that would be 16 days, right?
1/√2 * 1/√2 = 1/2