Asked by Anonymous
                In each of the following groups, identify the two substances whose aqueous solutions have common properties to a marked degree by circling the two formulas. Explain why you made your choice.
I'm not the two formulas I circle is correct. Below are my explanations. Fix me where I am wrong. I appreciate your help!
a) CuS, CuCl2, Na2S, KCl
I know CuS, copper (II) sulfide is insoluble, but CuCl2,copper (II) chloride, Na2S, Sodium Sulfide, and KCl, Potassium Chloride, are soluble. The two out of the three (in which I will circle) I see common characteristics are CuCl2 and KCl, since they both have cations of Cl^-.
b) HCl, HC2H3O2, NaC2H3O2
I'd circle HCl, hydrochloric acid, and NaC2H3O2, Sodium Acetate, because they are strong electrolytes.
            
        I'm not the two formulas I circle is correct. Below are my explanations. Fix me where I am wrong. I appreciate your help!
a) CuS, CuCl2, Na2S, KCl
I know CuS, copper (II) sulfide is insoluble, but CuCl2,copper (II) chloride, Na2S, Sodium Sulfide, and KCl, Potassium Chloride, are soluble. The two out of the three (in which I will circle) I see common characteristics are CuCl2 and KCl, since they both have cations of Cl^-.
b) HCl, HC2H3O2, NaC2H3O2
I'd circle HCl, hydrochloric acid, and NaC2H3O2, Sodium Acetate, because they are strong electrolytes.
Answers
                    Answered by
            DrBob222
            
    I don't see anything wrong with your answers; however, I think it is a poor question. For example, in question (a), why not include Na2S since that is soluble along with CuCl2 and KCl. All three are quite soluble so I would say that was to a marked degree. KCl and CuCl2 DO have the Cl^- as common ions.
For question (b), you are correct that HCl and NaC2H3O2 are strong electrolytes ( but only in solution), but why not include NaC2H3O2 and HC2H3O2 because both contain the acetate ion (although not to a marked degree (and to what extent is a "marked degree"?) since acetic acid is only slightly ionized). HCl with no (aq) after it or something to indicate it is solution, is a gas and is not ionized. Or could HCl and HC2H3O2 both contain hydrogen atoms. I just don't think these are good questions at all.
I hope I've not confused you.
    
For question (b), you are correct that HCl and NaC2H3O2 are strong electrolytes ( but only in solution), but why not include NaC2H3O2 and HC2H3O2 because both contain the acetate ion (although not to a marked degree (and to what extent is a "marked degree"?) since acetic acid is only slightly ionized). HCl with no (aq) after it or something to indicate it is solution, is a gas and is not ionized. Or could HCl and HC2H3O2 both contain hydrogen atoms. I just don't think these are good questions at all.
I hope I've not confused you.
                    Answered by
            Anonymous
            
    opps I forgot to add NH4C2H3O2 to the list of substances for part (b)
a) CuCl2 and KCl - both soluble and have chlorine ion as anion.
b) NH4C2H3O2 and NaC2H3O2 - both soluble and have acetate ion as anion
    
a) CuCl2 and KCl - both soluble and have chlorine ion as anion.
b) NH4C2H3O2 and NaC2H3O2 - both soluble and have acetate ion as anion
                    Answered by
            Katrina
            
    SO3 can be produced in the following two-step process: 
FeS2 + O2 ---> Fe2O3 + SO2
S02 + O2 ----> SO3
Assuming that all the FeS2 reacts, how many grams of SO3 are produced when 20.0 g of the FeS2 reacts with 16.0 g of O2?
    
FeS2 + O2 ---> Fe2O3 + SO2
S02 + O2 ----> SO3
Assuming that all the FeS2 reacts, how many grams of SO3 are produced when 20.0 g of the FeS2 reacts with 16.0 g of O2?
                    Answered by
            DrBob222
            
    Katrina-
Please go to the to of the page, click on Post a New Question, and post your question. You will get better service that way.
    
Please go to the to of the page, click on Post a New Question, and post your question. You will get better service that way.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.