Question

In determing the simplest formula of lead sulfide, 2.46 grams of of lead are placed in a crucible with 2.00 grams of sulfur. when the reaction is complete, the product has a mass of 3.22 grams. What mass of sulfur should be used in the simplest formula calculation? Find the simplest formula of lead sulfide

Answer 1

mass Pb = 2.46g.
mass S = 3.22-2.46 = ?

Convert 2.46g to mols. mol = g/atomic mass
mols S = (3.22-2.46)/atomic mass S.

Now find the ratio of the elements to each other to determine the empirical formula.

Answer 2

3.22-2.46=.76.

Answer 3

Now mols Pb = grams/atomic massPb
mols S = grams/atomic mass S

Then find ratio of the elements to each other.