In DABC,∠Q >∠R, PA is the bisector of
∠ QPR and PM is perpendicular to BQ. Prove that ∠APM = half of ( ∠Q - ∠R )
∠ QPR and PM is perpendicular to BQ. Prove that ∠APM = half of ( ∠Q - ∠R )
1 answer
1 answer
1 answer
1 answer