The volume formula is:
volume = length x width x height
Plugging in the given measurements, we get:
volume = 3 3/4 feet x 2 1/2 feet x 2 1/2 feet
volume = (15/4) feet x (5/2) feet x (5/2) feet
volume = (375/16) cubic feet
volume = 23 7/16 cubic feet
Therefore, the volume of the toy box is 23 7/16 cubic feet.
In cubic feet, what is the volume of a toy box measuring 3 3/4 feet long, 2 1/2 feet wide, and 2 1/2 feet tall? Use the volume formula to solve. The answer will be a mixed fraction in cubic feet.(1 point)
5 answers
Using the formula V=B×h, what is the volume of a rectangular prism with a length of 7 1/4 m, a width of 10 1/2 m, and a height of 12 2/5 m? The answer will be a mixed fraction in cubic meters
We need to plug in the given values into the formula V = B x h, where B is the area of the base and h is the height:
B = length x width
B = (7 1/4 m) x (10 1/2 m)
B = (29/4 m) x (21/2 m)
B = (609/8) m^2
Now we can find the volume:
V = B x h
V = (609/8) m^2 x (12 2/5 m)
V = (609/8) m^2 x (62/5 m)
V = (18978/40) m^3
V = 474 3/4 m^3
Therefore, the volume of the rectangular prism is 474 3/4 cubic meters.
B = length x width
B = (7 1/4 m) x (10 1/2 m)
B = (29/4 m) x (21/2 m)
B = (609/8) m^2
Now we can find the volume:
V = B x h
V = (609/8) m^2 x (12 2/5 m)
V = (609/8) m^2 x (62/5 m)
V = (18978/40) m^3
V = 474 3/4 m^3
Therefore, the volume of the rectangular prism is 474 3/4 cubic meters.
Given the two coordinates (−6, 5), and (−6, 10), what is the distance between them on a coordinate plane?
The two coordinates share the same x-coordinate of -6 but have different y-coordinates. To find the distance between them, we need to find the difference between their y-coordinates:
distance = |y2 - y1|
distance = |10 - 5|
distance = 5
So the distance between the two coordinates is 5 units.
distance = |y2 - y1|
distance = |10 - 5|
distance = 5
So the distance between the two coordinates is 5 units.