coulombs = current x seconds
C = 0.5A x 100 min x (60 sec/min) = 3,000 C
0.00033 g/Coulomb x 3,000 coulombs = 0.99 g Cu deposited.
Now a problem. There is no way the density of Cu is 10,000 g/cc. The density of Cu is 8.96 g/cc so I will round that off as 9 g/cc. You may have meant to round it to 10.000 g/cc.
mass Cu = volume x density
0.99 = volume x 9 g/cc
v = 0.99/9 = 0.11 cc
The area plated is 100 cm^2 or let's say 10 cm x 10 cm.
volume = length x width x thickness
0.11 = 10 x 10 x thickness. Solve for thickness. After you have corrected the problem for the density you can follow this procedure to determine the thickness. Post your work if you get stuck.
In copper plating, a current of 0.5A is allowed for a cathode area of 100cm2. If this current is maintained constant for 100mins, calc. the thickness of the copper deposited. [electrochemical equivalent of copper=0.00033gC-1, density of copper=10000gcm-3]
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