Since the angles in a triangle always add up to 180 degrees, we can find M<BOA by subtracting the other two angles from 180:
M<BOA = 180 - 118 - 126 = 64
Now, since AC is a diameter (which means it passes through the center of the circle O), we know that M<BOA + M<BOC = 180. Plugging in values, we get:
64 + 126 = 180
Simplifying, we get:
M<ACB = 180 - 64 - 126 = 10
Therefore, mAC = M<ACB + M<ABC = 10 + (118/2) = 10 + 59 = 69 degrees.
In circle O, M<AOB = 118, and M<BOC = 126.
What is mAC
1 answer