To determine the force required on the small piston, we can use the principle of Pascal's law, which states that the pressure applied to a fluid is transmitted uniformly in all directions.
First, let's calculate the pressure applied on the large piston. We can use the formula:
Pressure = Force / Area
The area of the large piston is 28.27 cm^2, and the force lifted by the jack is 7468 N.
Pressure on the large piston = 7468 N / 28.27 cm^2
Now, according to Pascal's law, this pressure will be transmitted uniformly to the small piston as well.
Let's assume the force required on the small piston is F.
Using the same principle, we have:
Pressure on the small piston = F / 1.325 cm^2
Since the pressure is transmitted uniformly, the pressures on both pistons are equal.
Pressure on the large piston = Pressure on the small piston
7468 N / 28.27 cm^2 = F / 1.325 cm^2
To find F, we can rearrange the equation:
F = (7468 N / 28.27 cm^2) * 1.325 cm^2
F ≈ 350.67 N
Therefore, approximately 350.67 N of force must be exerted on the small piston.
In changing a tire a hydraulic jack lifts 7468 N on its large piston which has an area of 28.27 cm^2 how much force must be excreted on the small piston if it has an area of 1.325 cm^2
1 answer
1 answer