To analyze the situation with the artificial cell containing a 45% glucose solution immersed in a beaker with a 55% glucose solution, let's break down the answers:
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Direction of solute movement: The solute (glucose) will move from an area of lower concentration to an area of higher concentration. In this case, the concentration of glucose is lower in the cell (45%) compared to the beaker (55%). Therefore, the movement of glucose will be: Answer: b. out of cell.
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Direction of solvent movement: The solvent in this case is water, which will move from an area of higher concentration of solvent (lower solute concentration) to an area of lower concentration of solvent (higher solute concentration). Since the cell has a 45% glucose solution, it has a higher concentration of water compared to the 55% glucose solution in the beaker. Therefore, the movement of water will be: Answer: a. into cell.
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Percentage of solute and solvent in the artificial cell: In the artificial cell containing a 45% glucose solution, the percentage of solute (glucose) is 45%. The percentage of solvent (water) can be calculated as follows: \[ \text{Percentage of solvent} = 100% - \text{Percentage of solute} = 100% - 45% = 55% \] Therefore: Answer: The percentage of solute = 45%, and the percentage of solvent = 55%.
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Changes that would occur after the cell is placed into the beaker:
- The glucose will diffuse out of the cell into the beaker until equilibrium is reached, which means the concentration of glucose inside the cell will decrease.
- Water will move into the cell from the beaker to dilute the glucose concentration, potentially increasing the volume of the cell and causing it to swell.
- Depending on the osmotic pressure and the permeability of the membrane, the overall effect could lead to the cell swelling or even bursting if too much water enters.
In summary, the cell will experience changes in both solute and solvent concentrations as they move in response to the concentration gradients.