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In an old house, the heating system uses radiators, which are hollow metal devices through which hot water or steam circulates....Asked by StressedStudent
In an old house, the heating system uses radiators, which are hollow metal devices through which hot water or steam circulates. In one room the radiator has a dark color (emissitivity = 0.804). It has a temperature of 65.9 oC. The new owner of the house paints the radiator a lighter color (emissitivity = 0.439). Assuming that it emits the same radiant power as it did before being painted, what is the temperature (in degrees Celsius) of the newly painted radiator?
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Answered by
drwls
(emissivity)*sigma*T^4 = constant
sigma is the Stefan-Bolzmann constant, which cancels out.
T must be in Kelvin
(0.804)*sigma*339.1^4 = (0.439)*sigma*T^4
(T/339.1)^4 = 1.8314
T/339.1 = 1.163
T = 394.5 K = 121 C
sigma is the Stefan-Bolzmann constant, which cancels out.
T must be in Kelvin
(0.804)*sigma*339.1^4 = (0.439)*sigma*T^4
(T/339.1)^4 = 1.8314
T/339.1 = 1.163
T = 394.5 K = 121 C
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