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In an isosceles triangle angle in the top vertex is twice the sum of the base angle. Find the exterior angles of the triangle.

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Let vertex is x
Basa angles are 2x
We know that
Sum of angles in triangle is 180
X+2x+2x=180
5x= 180
X=36
Base angle=2(36)
=72
Exterior angles = sum of interior angles
=72+72
=144

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