Set up an ICE chart with P = pressure NH3 initially. Total P at equilibrium is 10 atm. If it is 96% dissociated, then you lose 0.96P NH3, form 1/2 that for N2 and form 3/2 that for H2.
...........2NH3 ==> N2 + 3H2
I...........P......0......0
C........-0.96P...0.48P..1.44P
E.........0.04P..0.48P...1.44P
Total P = pNH3 | pN2 + pH2
10 = 0.04p + 0.48P + 1.44P
10 = 1.96p
p = 10/1.96 = about 5 but you need it more accurate than that.
Calculate pressure of each and substitute into Kp expression to solve for Kp.
In an experiment, at a total pressure of 10atm and 400 degree celcius, the equilibrium mixture 2NH3=N2+3H2 the ammonia was found to have dissociated to the extent of 96%. Calculated Kp for the rxn. (reversible rxn).
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