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In an experiment a student allowed benzene C6H6+ TO REACT WITH EXCESS BROMINE BR2+ In an attempt to prepare bromobenzene C6H5Br...Asked by Sunny
In an experiment a student allowed benzene C6H6, TO REACT WITH EXCESS BROMINE BR2, in an attempt to prepare bromobenzene C6H5Br. This reaction also produced as a by-product, dibromobenzene, C6H4Br2, On the basis of the equation.
C6H6 + Br2 -> c6h5Br + H Br
a)What is the maximum amount of C6H5Br that the student could have hoped to obtain from 15.0 g of benzene? (This is the theoretical yield.)
b)In this experiment the student obtained 2.50 C6H5Br2, How much C6H6 was not converted to C6H5Br?
c)What is the student’s actual yield of C6H5Br?
d)Calculate the percentage yield for the reaction?
C6H6 + Br2 -> c6h5Br + H Br
a)What is the maximum amount of C6H5Br that the student could have hoped to obtain from 15.0 g of benzene? (This is the theoretical yield.)
b)In this experiment the student obtained 2.50 C6H5Br2, How much C6H6 was not converted to C6H5Br?
c)What is the student’s actual yield of C6H5Br?
d)Calculate the percentage yield for the reaction?
Answers
Answered by
DrBob222
See your earlier post under dolly.
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