In an experiment a student allowed benzene C6H6+ TO REACT WITH EXCESS BROMINE BR2+ In an attempt to prepare bromobenzene C6H5Br. This reaction also produced as a by-product, dibromobenzene, C6H4Br2+ On the basis of the equation.

Question

In an experiment a student allowed benzene C6H6+ TO REACT WITH EXCESS BROMINE BR2+ In an attempt to prepare bromobenzene C6H5Br.  This reaction also produced as a by-product, dibromobenzene, C6H4Br2+ On the basis of the equation.
What is the maximum amount of C6H5Br that the student could have hoped to obtain from 15.0 g of benzene? (This is the theoretical yield.)

DrBob222 · Answer

I don't get the C6H6+, Br2+ and C6H4B42+. Why the + signs?
You don't have them in the reaction.
Convert 15.0 g benzene to mols. mols = grams/molar mass.
Use the coefficients in the balanced equation to convert mols benzene to mols of the bromobenzene.
Now convert these mols to grams. g = mols bromobenzene x molar mass benzene.