In an experiment,20.0cm³ of a solution containing 4gdm-³ of sodium hydroxide was neutralized by 8.0cm³ of dilute tetraoxosulphate (vi) acid

1)Write the balanced equation
2) calculate the concentration of the acid in moldm³

1 answer

1) NaOH + H2SO4 -> Na2SO4 + 2H2O

2) To calculate the concentration of the acid, we need to use the equation:

Moles of acid = Moles of sodium hydroxide

Moles of sodium hydroxide = volume x concentration
Moles of sodium hydroxide = 20.0cm³ x 4gdm-³ / 1000g/mol = 0.08 mol

Moles of acid = volume x concentration
0.08 mol = 8.0cm³ x concentration / 1000cm³/L
Concentration of acid = 10 mol/L or 10M