In an examination 18 candidates passed mathematics 17 candidates passed physics 11 candidates passed both and 1 failed both find the number that passed physics and the total candidates

Answer 1

Let's call the number of candidates that passed physics as P and the total number of candidates as T.

According to the problem, there are 18 candidates that passed mathematics, 17 candidates that passed physics, and 11 candidates that passed both. We also know that 1 candidate failed both.

We can use the principle of inclusion-exclusion to find the number of candidates that passed physics.

Total number of candidates that passed:
= Number of candidates that passed mathematics + Number of candidates that passed physics - Number of candidates that passed both
= 18 + 17 - 11
= 24

So, the number of candidates that passed physics is 24.

To find the total number of candidates, we add the number of candidates that passed physics with the number of candidates that failed both.

Total number of candidates = Number of candidates that passed physics + Number of candidates that failed both
= 24 + 1
= 25

Therefore, the total number of candidates is 25.