In an election,there were three candidates 3/7 of the electors voted for the winner.The runner up received 5/8 of the remaining votes.What fractions of the electors voted for the third candidate.If the winner received 3021 votes more than the runner up.How many electors voted.

Answer 1

winner: 3/7, leaving 4/7
runner-up: 5/8 * 4/7 = 5/14
loser: 1 - 3/7 - 5/14 = 3/14
total: 3/7 x = 5/14 x + 3021
...

Answer 2

Good

Answer 3

I need an answer to this equation

Answer 4

In an election there were three candidates .3/7 of the electors voted for the winner . The runner up received 5/8 of the remaining votes.
A) what fraction of the electors voted for the third cadidate.
B) if the winner recieved 3021 voted than the runner up how many electors voted

Answer 5

Let's say that there were x electors in total.

3/7 of them voted for the winner, so that's 3/7x votes.

That leaves 4/7x electors remaining.

The runner-up received 5/8 of the remaining votes, which is (5/8) * (4/7x) = 5/14x votes.

That leaves (4/7x - 5/14x) = 3/14x votes for the third candidate.

We're also told that the winner received 3021 more votes than the runner-up, so:

3/7x = 5/14x + 3021

Multiplying both sides by 14 (the least common multiple of 7 and 2), we get:

6x = 5x + 42,294

Simplifying, we get:

x = 42,294

So there were 42,294 electors in total.

To find out what fraction of the electors voted for the third candidate, we need to divide their votes (3/14x) by the total number of electors (42,294):

(3/14) * (42,294) = 9,078

So 9,078 electors (or 3/14 of the total) voted for the third candidate.