since distance = speed * time,
120t = 105(t + 1/3)
solve for t, then find the distance
In an automobile race, the rate of one car was 120 mi/hr and the rate of another was 105 mi/hr. If the faster car finished the race 20 minutes before the slower one, what was the distance of the race?
2 answers
In an automobile race, the rate of one car was 120 mi/hr and the rate of another was 105 mi/hr. If the faster car finished the race 20 minutes before the slower one, what was the distance of the race?