In an automobile race, the rate of one car was 120 mi/hr and the rate of another was 105 mi/hr. If the faster car finished the race 20 minutes before the slower one, what was the distance of the race?

Answer 1

since distance = speed * time,

120t = 105(t + 1/3)

solve for t, then find the distance

Answer 2

In an automobile race, the rate of one car was 120 mi/hr and the rate of another was 105 mi/hr. If the faster car finished the race 20 minutes before the slower one, what was the distance of the race?