The acceleration rate a can be derived from
0.51 m = (1/2)*a*t^2
a = 1.02 m/s^2
The equation of motion will tell you a in terms of M1, M2 and I/R^2.
For a derivatkion, see
http://en.wikipedia.org/wiki/Atwood_machine
Solve for I
Knowing the acceleration and the masses will also let you solve for the tenskion on both sides of the pulley
In an Atwood machine, one block has a mass of M1 = 520 g and the other has a mass of M2 = 320 g. The frictionless pulley has a radius of 4.6 cm. When released from rest, the heavier block moves down 51 cm in 1.00 s (no slippage). What is the tension T1? Find the pulley's moment of inertia.
2 answers
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