Asked by Marie
In an arithmetic sequence where a6=13 and a10=25, what is the explicit formula for the general term an?
Answers
Answered by
Jai
an = ao + (n-1)d
where
an = the nth term
ao = the first term
n = number of terms
d = difference between two consecutive terms
Substituting the given,
(i) a6 = 13 (here, n=6, an=13)
13 = ao + (6-1)d
13 = ao + 5d
(ii) a10 = 25 (here, n=10, an=25)
25 = ao + (10-1)d
25 = ao + 9d
Now we have two linear equations. We can do elimination method to get d:
13 = ao + 5d
-(25 = ao + 9d)
--------------------------
-12 = -4d
d = 12/4
d = 3
Solving for ao,
13 = ao + 5(3)
13 = ao + 15
ao = 13 - 15
ao = -2
Therefore, the general expression for an:
an = -2 + 3*(n-1)
Hope this helps~ `u`
where
an = the nth term
ao = the first term
n = number of terms
d = difference between two consecutive terms
Substituting the given,
(i) a6 = 13 (here, n=6, an=13)
13 = ao + (6-1)d
13 = ao + 5d
(ii) a10 = 25 (here, n=10, an=25)
25 = ao + (10-1)d
25 = ao + 9d
Now we have two linear equations. We can do elimination method to get d:
13 = ao + 5d
-(25 = ao + 9d)
--------------------------
-12 = -4d
d = 12/4
d = 3
Solving for ao,
13 = ao + 5(3)
13 = ao + 15
ao = 13 - 15
ao = -2
Therefore, the general expression for an:
an = -2 + 3*(n-1)
Hope this helps~ `u`
Answered by
Anonymous
3n-5
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