monitor A 22:12:06
monitor B 22:54:07
diff. = 42:01
42 min 1 sec = 42 + 1/60
42 min 1 sec = 42.01667 min
42.01667/60 = 0.700278 hr
R = D/T
R = 62/.700278
R = 88.53627 km/hr
R = 88.54 km/hr
check
D = RT
D = 88.54 x .70
D = 61.978
62 = 61.978
I am not a tutor
In an ANPR system the time that a vehicle passes a monitoring point is recorded. A suspicious vehicle can be tracked along the motorway by noting the time it passes each ANPR monitoring point. If a car passes monitor A at 22.12.06 and monitor B at 22.54.07 and the monitors are 62 km apart calculate the average speed of the vehicle between the two monitoring points. Express your answer in km/hour to 2 decimal places.
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1 answer