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In an amusement park rocket ride, cars are suspended from L = 4.28-m cables attached to rotating arms at a distance of d = 6.10...Asked by Jon Tuck
In an amusement park ride, cars are suspended from L = 4.22 m cables attached to rotating arms at a distance of D = 6.25 m from the axis of rotation. The cables swing out at an angle of θ = 49° when the ride is operating. What is the angular speed of rotation?
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Answered by
drwls
Do they want it in radians per second or revolutions per minute?
V^2/(R*g) = tan 49 = 1.150
R = L sin49 = 3.04 m
V^2 = 34.3 m^2/s^2
V = 5.86 m/s
The angular speed in radians/sec is V/R
V^2/(R*g) = tan 49 = 1.150
R = L sin49 = 3.04 m
V^2 = 34.3 m^2/s^2
V = 5.86 m/s
The angular speed in radians/sec is V/R
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