In △ABC, m∠ACB=90°, m∠ACD=60°,

Question

CD
is the altitude to
AB
, and BD = 5 cm. Find AD.

(A) 6cm (B) 15cm (C) 20cm (D) 25cm

Answer 1

After you make your sketch, you will realize that your are dealing
with 3 similar triangles with angles 30°, 60°, 90°
with corresponding sides in the ratio of 1 : √3 : 2
So should be easy to see with simple ratios that CD = 5√3 and x = 15

or, ..... you could just use basic trig
In triangle BCD, tan60° = CD/5
√3 = CD/5
CD = 3√5 , as above
Now in triangle ADC, tan60° = x/CD
x = CDtan60°
= (3√5)(√3) = 15 , as above

Answer 2

answer is 15