in a triangle the sum of the angle is 180degrees. if angle A is three times angle B and Angle C is 10 degrees more than twice Angle A. Find the measures of the three anges to the newarest degree

Answer 1

A = 3B or B = A/3

C = 2A + 10 or

A + B + C = 180

A + A/3 + (2A+10) = 180

Solve for A, then B and C.

Answer 2

A = 3 B

C = 2 A + 10 °

C = 2 * 3 B + 10 °

C = 6 B + 10 °

A + B + C = 180 °

3 B + B + 6 B + 10 ° = 180 °

10 B + 10 ° = 180 ° Subtract 10 ° to both sides

10 B + 10 ° - 10 ° = 180 ° - 10 °

10 B = 170 ° Divide both sides by 10

B = 17 °

A = 3 * B = 3 * 17 = 51 °

C = 6 B + 10 °

C = 6 * 17 ° + 10 ° = 102 ° + 10 ° = 112 °

Proof :

A + B + C = 51 ° + 17 ° + 112 ° = 180 °