Nope. 15/17 = cosG
cosH = sinG
Draw the triangle to see this.
The "co" in cosine means sine of the complementary angle.
In a triangle, GHI, if sin G = 8/17 then what is the value of cos H?
A). 8/17
B). 15/8
C). 15/17***
D). 17/8
5 answers
looking at the numbers showing up , I can see that
15^2 + 8^2 = 17^2
thus suggesting that you have a right-angled triangle.
You did not state that all important information.
Assuming that angles G and H are the acute angles of such a triangle
we know that sin G = cos(90°- G) = cos H , since G and H must be complimentary angles
so cos H = 8/17
15^2 + 8^2 = 17^2
thus suggesting that you have a right-angled triangle.
You did not state that all important information.
Assuming that angles G and H are the acute angles of such a triangle
we know that sin G = cos(90°- G) = cos H , since G and H must be complimentary angles
so cos H = 8/17
@oobleck I assumed since the denominator was 17, that meant that the answer should have the same amount as what was in the question
@Spring, please be polite here, whether to tutors or other students.
To indicate a website, all you have to do is omit the https:// part, and the rest will paste just fine. All tutors know this. Be sure you give it a try.
To indicate a website, all you have to do is omit the https:// part, and the rest will paste just fine. All tutors know this. Be sure you give it a try.
Spring, you are correct. So?
1 answer