In a titration experiment, 20.4 mL of 0.883 M 𝐻𝐶𝑂𝑂𝐻 neutralize 19.3 mL of 𝐵𝑎(𝑂𝐻)2. What is the concentration of the 𝐵𝑎(𝑂𝐻)2 solution?

Answer 1

2HCOOH + Ba(OH)2 ==> Ba(OOCH)2 + 2H2O
mols HCOOH = M x L = ?
Looking at the balanced equation,mols Ba(OH)2 is 1/2 mols HCOOH.\
Then M Ba(OH)2 = mols BaOH)2/L Ba(OH)2 = ?