In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garic in a processed tablet form. Cholesorol levels were measured before and after the treament. the changes in their levels of LDL cholestorol (in mg/dL have a mean of 3.5 and a standard deviation of 17.7
3 answers
What is your question?
It says "Construct a 99% confidence interval estimate of the mean net change in
LDL cholestorol after the garlic treatment. What does the confidense interval
suggest about the effectiveness of garlic in reducing LDL cholestorol?
What is the confidence interval estimate of the population mean μ?
___mg/dL < μ < ___mg/dL
I just don't get how to solve this
LDL cholestorol after the garlic treatment. What does the confidense interval
suggest about the effectiveness of garlic in reducing LDL cholestorol?
What is the confidence interval estimate of the population mean μ?
___mg/dL < μ < ___mg/dL
I just don't get how to solve this
99% = mean ± 2.575 SEm
SEm = SD/√n
SEm = SD/√n