In a survey of the 100 out-patients who reported at a hospital one day it was found out that 70 complained of fever 50 complained of stomach ache and 30 were injured all 100 patients had at least one the complaint and 44 had exactly 2 of the complaint how many patients had all the three complaints

Answer 1

70+50+30 - (44+3x) + x = 100
x = 3