In a survey of 1500 residents of a city, 34% said that they regularly eat organic foods.

The margin of error is $2.6%
Give an interval that is likely to contain the exact percentage of residents in the city who regularly eat organic foods.

The interval is from _% to _%.

1 answer

The interval is from 31.4% to 36.6%.

To calculate the interval, we take the 34%, which is the percentage from the survey, and then subtract the margin of error (34% - 2.6% = 31.4%) to get the lower bound.
Then, we add the margin of error to the survey percentage (34% + 2.6% = 36.6%) to get the upper bound.

Therefore, the interval is from 31.4% to 36.6%.