in a single throw fair die what is probability that an odd number or perfect square greater then one show up?

Answer 1

odds: 1,3,5
perfect squares: 1, 4

I count 4 possibilities, so .....

Answer 2

described me the answer I am not agreed

Answer 3

I am not agreed the answer describe it again

Answer 4

I had hoped your could continue,

so we have 4 cases,
prob(odd or perfect square) = 4/6 = 2/3