odds: 1,3,5
perfect squares: 1, 4
I count 4 possibilities, so .....
in a single throw fair die what is probability that an odd number or perfect square greater then one show up?
4 answers
described me the answer I am not agreed
I am not agreed the answer describe it again
I had hoped your could continue,
so we have 4 cases,
prob(odd or perfect square) = 4/6 = 2/3
so we have 4 cases,
prob(odd or perfect square) = 4/6 = 2/3