Question

In a school, all students play either Chess or Carom or both. 400 play Carom, 150 play Chess, and 130 play both games. Find the number of students who play Carom only.

Answer 1

To find the number of students who play only Carom, we can use the principle of inclusion-exclusion.

Let's denote:

- \( C \): the number of students who play Carom
- \( H \): the number of students who play Chess
- \( B \): the number of students who play both games

From the problem, we have:

- \( C = 400 \)
- \( H = 150 \)
- \( B = 130 \)

The number of students who play only Carom is given by the formula:

\[
\text{Carom only} = C - B
\]

Substituting the values we have:

\[
\text{Carom only} = 400 - 130 = 270
\]

Thus, the number of students who play Carom only is \( \boxed{270} \).