In a school, all students play either Chess or Carom or both. 400 play Carom, 150 play Chess, and 130 play both games. Find the number of students who play Carom only.

Answer 1

To find the number of students who play only Carom, we can use the principle of inclusion-exclusion.

Let's denote:

• \( C \): the number of students who play Carom
• \( H \): the number of students who play Chess
• \( B \): the number of students who play both games

From the problem, we have:

• \( C = 400 \)
• \( H = 150 \)
• \( B = 130 \)

The number of students who play only Carom is given by the formula:

\[ \text{Carom only} = C - B \]

Substituting the values we have:

\[ \text{Carom only} = 400 - 130 = 270 \]

Thus, the number of students who play Carom only is \( \boxed{270} \).