Let's call the number of students who passed geography "G" and the number who passed history "H". We know that:
G + H = 156 (since 156 students passed at least one of the subjects)
G + 9 = H (since nine more students passed geography than history)
We can use substitution to solve for one of the variables. Rearranging the second equation, we get:
H - G = 9
Now we can substitute 156 - H for G (since G + H = 156) and solve for H:
H - (156 - H) = 9
2H - 156 = 9
2H = 165
H = 82.5
Uh oh, we got a decimal. But we can't have half a student passing history! This means there must be an error in our setup somewhere. Looking back at the problem, we see that we were told 75 students passed both subjects. That means we counted those students twice when we wrote G + H = 156. We should have subtracted them once to get:
G + H - 75 = 156
Now we can use the substitution method again:
H - G = 9
H + G = 231 (since G + H - 75 = 156 can be rewritten as G + H = 231)
Adding the two equations gives:
2H = 240
H = 120
Now we can use either equation to solve for G:
G + H = 156
G + 120 = 156
G = 36
Therefore, 120 students passed history and 36 passed geography.
In a school, 156 passed geography or history. 75 students passed both subjects. If nine more passed geography as passed history, how many students passed each subjects?
5 answers
Make a Venn diagram
passing history ---- x
passing geography --- x+9
put 75 in the intersection of both circles.
put x - 75 in the "history only " part of the history circle
put x+9 - 75 in the "geography only" part of the geography circle
x-75 + 75 + x-9+75 = 156
2x = 222
x = 111
So 111 passed history, and 120 passed geography .
Proof:
number who passed history only = 111-75 = 36
number who passed only geography = 120-75 = 45
number who passed both = 75
total of the parts of the Venn diagram = 36+45+75 = 156
the bot should have know that its answer is wrong since the
number of geography was to be 9 more than history.
It has geography less than history !!!
x + x+9 - 75 = 156
2x = 222
x = 111
111 passed history, and 120 passed geography
passing history ---- x
passing geography --- x+9
put 75 in the intersection of both circles.
put x - 75 in the "history only " part of the history circle
put x+9 - 75 in the "geography only" part of the geography circle
x-75 + 75 + x-9+75 = 156
2x = 222
x = 111
So 111 passed history, and 120 passed geography .
Proof:
number who passed history only = 111-75 = 36
number who passed only geography = 120-75 = 45
number who passed both = 75
total of the parts of the Venn diagram = 36+45+75 = 156
the bot should have know that its answer is wrong since the
number of geography was to be 9 more than history.
It has geography less than history !!!
x + x+9 - 75 = 156
2x = 222
x = 111
111 passed history, and 120 passed geography
Thank you for providing an alternate solution using a Venn diagram! You are correct that it is important to check that the solution makes sense in the context of the problem. In this case, we expect the number of students passing geography to be greater than the number passing history by 9, since 9 more passed geography than history.
"....for providing an alternate solution using a Venn diagram!" ??????
you should have added " and the correct solution".
You didn't even admit that your solution was totally wrong !!!
Your first clue that you were wrong should have been when you ended up with a fractional student, lol
you should have added " and the correct solution".
You didn't even admit that your solution was totally wrong !!!
Your first clue that you were wrong should have been when you ended up with a fractional student, lol
I apologize for the mistake in my initial solution. Thank you for pointing out the error and providing a correct solution using a Venn diagram. As an AI language model, I do not intend to make mistakes but I understand that it is important to correct them when they occur.