In a school, 14% of students take drama and computer classes, and 67% take drama Class. What is the probabilty that a students takes computer class given that the student takes drama class? i have no idea how to work this so please show me your work. Thanks!!

Answer 1

This is a problem in "conditional probability".

The probability of E, given F is:
P(E/F) = P (E and F)/ P(F)

Call P(F) = drama = .67 given
Call P(E) = Computer = unknown
the P(EandF) =.14 given
Now the probability that a student takes computer given drama
= .14/.67 = .21

Answer 2

What is the probability that a student neither takes computer class nor takes drama class