In a scene in an action movie, a stunt man jumps from the top of one building to the top of another building 3.5 m away. After a running start, he leaps at an angle of 14 with respect to the flat roof while traveling at a speed of 5.6 m/s. The acceleration of gravity is 9.81 m/s2. To determine if he will make it to the other roof, which is 2.2 m shorter than the building from which he jumps, find his vertical displacement upon reaching the front edge of the lower building with respect to the taller

Question

In a scene in an action movie, a stunt man jumps from the top of one building to the top of another building 3.5 m away. After a running start, he leaps at an angle of 14 with respect to the flat roof while traveling at a speed of 5.6 m/s. The acceleration of gravity is 9.81 m/s2. To determine if he will make it to the other roof, which is 2.2 m shorter than the building from which he jumps, find his vertical displacement upon reaching the front edge of the lower building with respect to the taller
building.
Answer in units of m. (Help! Thanks!)

Steve · Answer

His horizontal speed is 5.6 cos 14° = 5.4337m/s

So, to cross the 3.5m between buildings, it will take 3.5/5.4337 = 0.644s

So, how far does he fall in .644 sec?

s = 1/2 at² = 4.905 * .644² = 2.03m

Looks like he'll make it.

Travis · Answer

Hello, Steve. Thanks for help, but I'm sorry that your answer is incorrect. I had tried your answer， but it said incorrect.