so, if the acute angles are 6x and 13x, that means that
6x+13x=90
x = 90/19
and the other two angles are
540/19 and 1170/19
or, we might have
90=13x, so one of the other angles is 6x, and we have the third angle z as
90 + (6/13)(90) + z = 180
z = 630/13
Why cannot 90 be 6x?
In a right angled triangle, two of the angles are in the ratio 6:13. Find the 3rd angle
1 answer