In a right angled triangle, the length of a hypotenuse is 10 cm. Of the two shorter sides, one side is 2 cm longer than the other side. i) Find the lengths of the two shorter sides. ii)Hence, find the area of the triangle.

Answer 1

this is a Pythagorean triple
... 3-4-5 times 2 ... 6-8-10

x^2 + (x + 2)^2 = 10^2

2x^2 + 4x - 96 = 0

x^2 + 2x - 48 = 0

(x + 8) (x - 6) = 0

x = 6 ... x + 2 = 8

Answer 2

1m