In a rhombus ABCD, m∠A = 31°. Point O is a point of intersection of diagonals. Find the measures of the angles of triangle ΔBOC.
I got 15.5 degrees for angle OCB and thats right all I need is the angles for OBC and BOC
4 answers
note that ΔBOC is a right triangle, since the diagonals are perpendicular.
<BOC = 90
<OBC = 74.5
<OBC = 74.5
why does everyone keep getting BOC=90?
that is wrong.
that is wrong.
m∠BOC = 90 degrees
, m∠OCB = 15.5 degrees
, m∠OBC = 74.5 degrees
, m∠OCB = 15.5 degrees
, m∠OBC = 74.5 degrees
1 answer