In a reaction of ammonia production (NH3), 360g of nitrogen gas (N2) was reacted, generating a yield of 20%. What was the mass obtained from ammonia?

Answer 1

I guess this is the Haber process:

N2 + 3H2 ---> 2NH3

360g*(mole/28.0134g)= moles of N2

moles of N2*(2 moles of NH3/1 mole of N2)= moles of NH3

Moles of NH3*(17.03g/mole)= 100% yield

0.20*(100% yield)=NH3 produced